Index Of The — Matrix 1999 __hot__

Let ( J_n(0) ) be an (n \times n) Jordan block with zeros on the diagonal. Then [ \textrank(J_n(0)^k) = n - k \quad \textfor k=0,1,\dots, n, ] so (\textind(J_n(0)) = n).

If you want, give me the specific matrix labeled “1999” (or upload it) and I’ll compute its index (determinant or invariant-factor product) explicitly. index of the matrix 1999